How many molecules are in 0.25 mol of carbon(IV) oxide? (Avogadro's constant = 6.02 × 10²³ mol⁻¹)
Answer: A. Number of particles = moles × Avogadro's constant = 0.25 × 6.02 × 10²³ = 1.505 × 10²³.
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How many molecules are in 0.25 mol of carbon(IV) oxide? (Avogadro's constant = 6.02 × 10²³ mol⁻¹)
Answer: A. Number of particles = moles × Avogadro's constant = 0.25 × 6.02 × 10²³ = 1.505 × 10²³.
A gas occupies 66 cm³ at 27 °C. Find its volume at 77 °C, pressure remaining constant.
Answer: C. Charles's law uses kelvin: 27 °C = 300 K and 77 °C = 350 K. V₂ = 66 × 350 ÷ 300 = 77 cm³.
Express 0.5 mol/dm³ HNO₃ solution in g/dm³. (H = 1, N = 14, O = 16)
Answer: C. Mass concentration = molar concentration × molar mass = 0.5 × 63 = 31.5 g/dm³.
A current of 5 A flows for 11 minutes. Find the quantity of electricity passed.
Answer: B. Q = It = 5 × (11 × 60) = 3,300 C (time must be in seconds).
What is the pH of 0.00001 mol/dm³ nitric acid? (Assume it ionises completely.)
Answer: A. [H⁺] = 0.00001 = 10⁻⁵ mol/dm³, and pH = −log[H⁺] = 5.
Calculate the percentage by mass of nitrogen in NH₃. (N = 14, H = 1)
Answer: D. % of nitrogen = (mass of nitrogen in one formula unit ÷ molar mass) × 100 = 82.4%.
A test for hydrogen chloride is that the gas
Answer: C. Hydrogen chloride forms dense white fumes with ammonia.
What is the functional group of alkanones?
Answer: C. The functional group of alkanones is C=O within the chain (ketone).
What is the atomic number of carbon?
Answer: B. Carbon has 6 protons, so its atomic number is 6.
Which of these is a noble gas?
Answer: C. Argon is in Group 0 (Group 18), the noble gases.
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| Topic | Questions |
|---|---|
| Mole concept | 226 |
| Gas laws | 120 |
| Periodic table | 69 |
| Solutions | 67 |
| Atomic structure | 61 |
| States of matter | 61 |
| Electrolysis | 61 |
| Solubility | 60 |
| Chemical formulae | 40 |
| Organic chemistry | 38 |
| Acids, bases and salts | 18 |
| Redox | 18 |
| Gases | 14 |
| Separation techniques | 10 |